VALID 1Z0-071 TEST PREP, 1Z0-071 LATEST EXAM ONLINE

Valid 1z0-071 Test Prep, 1z0-071 Latest Exam Online

Valid 1z0-071 Test Prep, 1z0-071 Latest Exam Online

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Oracle Database SQL Sample Questions (Q207-Q212):

NEW QUESTION # 207
Examine the data in the CUST_NAMEcolumn of the CUSTOMERStable.

You want to extract only those customer names that have three names and display the * symbol in place of the first name as follows:

Which two queries give the required output? (Choose two.)

  • A. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME" FROM customers WHERE INSTR(cust_name, ' ',-1,2)<>0;
  • B. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME" FROM customers WHERE INSTR(cust_name, ' ',1,2)<>0;
  • C. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, '
    '), '*') "CUST NAME"
    FROM customers
    WHERE INSTR(cust_name, ' ',1,-2)<>0;
  • D. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, '
    '), '*') "CUST NAME"
    FROM customers
    WHERE INSTR(cust_name, ' ',1,2)<>0;

Answer: A,B


NEW QUESTION # 208
Examine the structure of the MEMBERS table:

Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC;
What would be the result execution? (Choose the best answer.)

  • A. It displays all cities in descending order, within which the last names are further sorted in descending order.
  • B. It fails because a column alias cannot be used in the ORDER BY clause.
  • C. It displays all cities in ascending order, within which the last names are further sorted in descending order.
  • D. It fails because a column number and a column alias cannot be used together in the ORDER BY clause.

Answer: C


NEW QUESTION # 209
View the exhibit and examine the data in ORDERS_MASTERand MONTHLY_ORDERStables.

Evaluate the following MERGEstatement:
MERGE_INTO orders_master o
USING monthly_orders m
ON (o.order_id = m.order_id)
WHEN MATCHED THEN
UPDATE SET o.order_total = m.order_total
DELETE WHERE (m.order_total IS NULL)
WHEN NOT MATCHED THEN
INSERT VALUES (m.order_id, m.order_total)
What would be the outcome of the above statement?

  • A. The ORDERS_MASTERtable would contain the ORDER_IDs1, 2 and 3.
  • B. The ORDERS_MASTERtable would contain the ORDER_IDs1, 2, 3 and 4.
  • C. The ORDERS_MASTERtable would contain the ORDER_IDs1, 2 and 4.
  • D. The ORDERS_MASTERtable would contain the ORDER_IDs1 and 2.

Answer: C

Explanation:
Explanation/Reference:
References:
https://docs.oracle.com/cd/B28359_01/server.111/b28286/statements_9016.htm


NEW QUESTION # 210
View the Exhibit and examine the description of the EMPLOYEES table.

Evaluate the following SQL statement:
SELECT first_name, employee_id, NEXT_DAY(ADD_MONTHS(hire_date, 6), 1) "Review" FROM employees; The query was written to retrieve the FIRST_NAME, EMPLOYEE_ID, and review date for employees. The review date is the firsts Monday after the completion of six months of the hiring. The NLS_TERRITORY parameter is set to AMERICA in the session.
Which statement is true regarding this query?

  • A. The query would execute but the output would give review dates that are Sundays.
  • B. The query would execute to give the desired output.
  • C. The query would not execute because date functions cannot be nested.
  • D. The query would not execute because the NEXT_DAY function accepts a string as argument.

Answer: A


NEW QUESTION # 211
You create a table by using this command:
CREATE TABLE rate_list (rate NUMBER(6,2));
Which two are true about executing statements?

  • A. INSERT INTO rate_list VALUES (-99.99) inserts the value as 99.99.
  • B. INSERT INTO rate_list VALUES (-10) produces an error.
  • C. INSERT INTO rate_list VALUES (-.9) inserts the value as -.9.
  • D. INSERT INTO rate_list VALUES (0.551) inserts the value as .55.
  • E. INSERT INTO rate_list VALUES (0.999) produces an error.
  • F. INSERT INTO rate_list VALUES (87654. 556) inserts the value as 87654.6.

Answer: C,D

Explanation:
The behavior of data insertion into a table with a specific numeric format in Oracle Database 12c can be explained as follows:
* A. INSERT INTO rate_list VALUES (-.9) inserts the value as -.9: This is correct. The value -.9 is within the precision defined by the table column (NUMBER(6,2)), where 6 is the total number of digits (including both sides of the decimal point), and 2 is the number of digits after the decimal point.
* E. INSERT INTO rate_list VALUES (0.551) inserts the value as .55: Oracle rounds the number to the nearest value that fits the specified scale of 2. Thus, 0.551 rounds down to 0.55.
References:
* Oracle Database SQL Language Reference 12c, particularly sections on data types and numeric precision.


NEW QUESTION # 212
......

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